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Help with C++ thanks.Question 1. Implement a C++ program and explain the syntax and use of data structures such as structures and class. Question 1a. Define a structure named Person using the C++ language to hold A string representing the name of the person. A float representing the BMI of the person. An integer representing the age of the person. A bool representing the Singapore nationality status of the person.Question 1b. Implement a main function to demonstrates the use of the structure defined in question 1a. The function declares an array of ten person items. Define the last element in the array as follows: name : “John Tan”, bmi : 25.12, age : 34, nationality : trueQuestion 1c.Modify the program in question 1a and 1b by converting the structure in question 1a to a C++ class. Implement a main function that performs the same tasks as required in question 1b using the C++ class you have just defined. Write your C++ code without changing the variable names described above. In addition, you may add your own variables if necessary but do not include other functions that are not needed here.
![Exercise 4A Write functions to perform the following tasks efficiently. Do not change the function names in the template file, and do not import any packages besides those already indicated in the template. (1) Take x and return 2x^3. (2) Take two inputs x and y and return their product and the absolute value of their difference, in that order. E.g. inputs 3,4 should return 12,1. (3) The geometric mean of n numbers is the nth root of their product. The mid-range is the ordinary (arithmetic) mean of the maximum and minimum elements. Write a function which takes a list of numbers as input and returns True if the geometric mean is less than or equal to the midrange, and False if the geometric mean is greater than the midrange. For example, the input [3,8,9] should return True and [3,6,7,5] should return False. (4) Take an integer n and return a list of the first n terms of the Padovan sequence pn. (This is a variant of the Fibonacci numbers, defined by p[1] = p[2] = p[3] = 1, and p[n] = p[n-2] + p[n-3] for n>=4.) (5) Take a pair r0 and theta representing a point's polar coordinates and return a pair (x,y) representing its Cartesian coordinates. (6) Take a pair (x,y) representing a point's Cartesian coordinates and return a pair (r, theta) representing its polar coordinates, where theta is in the range [0,2π). Check that your function works for (x,y) in all quadrants.](https://gotit-pro.com/wp-content/uploads/2023/10/69b0fd8b-79ad-4a6a-ac52-c635ef316302.jpg)
![(1) Write a function which takes a list of the coefficients of a polynomial P(x) = a0 + a1x + a2x^2 + ... + anx^n of arbitrary degree n, and a value of x0, and returns P(x0). You can use the function given in lectures, ensuring you understand how it works. (2) Use the function to evaluate (a) P1(x) = 4x^4 + 3x^2 + 2 at x = 2. (b) P2(x) = 241x^4 at x = 2. Are these answers exact? Explain why or why not. (Use a print statement to show the evaluation of your function, and answer the question in a comment.) (3) The power series for the sine function sin(x) is given by sin(x) = Σ (1)^n * (2n+1)! * x^(2n+1) = x - x^3/3! + x^5/5! - x^7/7! + ..., for all x. Use the first four terms in this series in the Horner evaluation function at a suitable value of x to give an approximation of sin(π/4). (4) (a) Use your Horner's method function to evaluate the polynomial (x-1)^3 at the point x = 1.000001. (b) Is this answer correct? (c) Briefly explain why or why not. (5) In week 3 we wrote a function to convert from binary to decimal. This can be adapted to other bases; here we will explore octal (base 8). The efficiency of the function we wrote can be improved using the same principle as Horner's method. Write such a function (horner_octal_to_dec) using the ideas of Horner's method which takes a list whose entries are integers between 0 and 7, where the list represents a base-8 number, and returns the corresponding decimal integer (so the input [2,5,1] returns the integer 169).](https://gotit-pro.com/wp-content/uploads/2023/10/627bbfd5-a1bb-4d60-954c-b70c3537706b.jpg)
![(b) Modify the program in Q3(a), with the following new rules: - Players will need to win 3 games to become the overall winner. - Implement a penalty - for the player who skipped, entered an incorrect expression, or entered an expression that evaluated to the wrong result, will draw 2 random digits into their hand. - The player who loses the game will be awarded a "Skip" card in the next game. With the "Skip" card, the player can hit < Enter > to skip, without a penalty. - If not utilized, the "Skip" cards CANNOT be carried forward to the next game. Illustration of the "new" game on the left column, with the rules of the game explained on the right column: Enter player: Alan Enter player: Betty Enter player: Starting hand (number) of digits: 4 Let's play... Game 1 Round 1: Result 6 Betty's hand: [5,2,1,1] Enter expression: 5+1 Correct! Betty's hand: [2,1] Alan wins this game in 4 rounds!! Overall game score: Alan 1, Betty 0 Let's play... Game 2 Round 1: Result 5 Betty's hand: [3, 6, 5, 7, 'S'] Enter expression: Skipped with no penalty!! Betty's hand: [3,6,5,7] Alan's hand: [2,1,2,1] Enter expression: Skipped and 2 digits added to hand Alan's hand: [2,1,2,1,4,7] Betty wins this game in 5 rounds!! Overall game score: Alan 1, Betty 1 Let's play... Game 3 Round 1: Result 6 Betty's hand: [1, 2, 8, 7] Enter expression: 8-2 Correct! Betty's hand: [1, 7] Computer randomized the play sequence and will stay the same for every game/round End of game, if no overall winner, continue to play another game. Loser will be awarded a "Skip" card in the next game. "S" represents the "Skip" card awarded to Betty. No penalty for Betty as she has a "Skip" card. Hit < Enter > key to skip if cannot form an expression. In this case, the player who skipped will draw 2 random digits into their hand. End of game, if no overall winner, continue to play another game. Loser will be awarded a "Skip" card in the next game.](https://gotit-pro.com/wp-content/uploads/2023/10/1fa83cc6-5755-4d51-b5f6-f4335b49f1c8.jpg)
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